A parallel plate capacitor is charged and then
isolated. What is the effect of increasing the plate
separation on charge, potential, capacitance,
respectively?
(a) constant, decreases, decreases
(b) increases, decreases, decreases
(c) constant, decreases, increases
(d) constant, increases, decreases
Answers
Answered by
11
Answer:
I think answet is (d) costant, increases, decreases
Answered by
1
Answer:
Explanation:Answer of this question is option d. Because C=epsilon not A/d. Also Q=CV. So from these 2 formula we get option d as answer.
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