Physics, asked by Mahesh3666, 9 months ago

A parallel plate capacitor is charged and then
isolated. What is the effect of increasing the plate
separation on charge, potential, capacitance,
respectively?
(a) constant, decreases, decreases
(b) increases, decreases, decreases
(c) constant, decreases, increases
(d) constant, increases, decreases

Answers

Answered by 1111kainatanjum
11

Answer:

I think answet is (d) costant, increases, decreases

Answered by sumitkale77272
1

Answer:

Explanation:Answer of this question is option d. Because C=epsilon not A/d. Also Q=CV. So from these 2 formula we get option d as answer.

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