Question

A parallel plate capacitor is charged by connecting it to a battery. The charge

on capacitor plates is q, with battery remaining connected, the plate separation is

doubled. The charge on capacitor plates is now _______​

Answer 1

Answer:

→constant because battery nemans connected.

E=

4

E

0

→k decreases

3.U=

2

1

CV

2

U is same but C become kC

So, U=

2

1

CV

2

⋅k(k increases)

i.e. Energy store ↑.

Answer 2

Answer:

now decreased by 2 times

Explanation: