A parallel plate capacitor is charged by connecting it to an ideal battery, the capacitor is then disconnected. Originally the energy stored in the capacitor is U∘. If the distance between the plates is doubled, then the new energy stored in the capacitor will be
Answers
Answered by
0
Explanation:
When battery is disconnected charge on capacitor is constant
We know C=
d
ε
0
A
when d is doubled C
1
=
2d
ε
0
A
∴Now C
1
=
2
C
Q=C
1
V
1
⇒V
1
=2
C
Q
=2V
∴E
1
=
2
1
C
1
0
V
1
2
=
2
1
⋅
2
C
⋅4V
2
=CV
2
II) When battery is connected V does not change
Now C
2
=
2d
ε
0
A
∴E
2
=
2
1
C
2
V
2
2
=
2
1
⋅(
2
C
)V
2
=
4.
CV
2
∴
E
2
E
1
=
4
CV
2
CV
2
=
Similar questions