Question

A parallel plate capacitor is charged to 60 micro C .Due to radioactive source the plate loses charges at the rate of 1.8 × 10^-8 Cs^-1. The magnitude of displacement current is

Answer 1

The displacement current in a capacitor is due to difference in the potential within the capacitor plates caused due to radioactive source. Therefore to find out displacement current we have to follow the following ways :-

1) The rate of loss of charge dQ/dt is

directly proportional to the

displacement current.

2) The proportionality constant is the

relative permeability of capacitor.

3) The displacement current is

obtained by multiplying the dQ/dt

with relative permeability being

1.257x10^-6 which gives

2.26x10^-14.