Question

A parallel plate capacitor is charged to a potential
difference of 50 V. It is discharged through a
resistance. After 1 second, the potential difference
between plates becomes 40 V. Then
(A) fraction of stored energy after 1 second
is 16/25.
(B) potential difference between the plates
after 2 seconds will be 32 V
(C) potential difference between the plates
after 2 seconds will be 20 V.
(D) fraction of stored energy after 1 second
is 4/5.
​

Answer 1

Explanation:

(A) fraction of stored energy after 1 second is 16/25.

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