Question

A parallel plate capacitor is made of two rectangular plates of area 1.0 m2 and the
separation between plates is 2.0 mm. A voltage of 100 V is applied across the
plates. Calculate the capacitance of the capacitor if a dielectric material of dielectric
constant 3.0 is introduced between the plates. What is the charge stored on each
plate of the capacitor?

Answer 1

A parallel plate capacitor is made of two rectangular plates of area 1.0 m2 and the

separation between plates is 2.0 mm. A voltage of 100 V is applied across the

plates. Calculate the capacitance of the capacitor if a dielectric material of dielectric

constant 3.0 is introduced between the plates. What is the charge stored on each

plate of the capacitor?

C = Kε₀ A / d

k = 3

ε₀ = 8.85  × 10⁻¹² F/m

A = 1 m²

d = 2 mm = 2 × 10⁻³ m

C = (3 × 8.85  × 10⁻¹² × 1) / (2 × 10⁻³)

C = 13.273 × 10⁻⁹ F

C = 13.273 nF

Capacitance = 13.273 nF

Voltage = 100 V

Q = CV

Q = 13.273 × 10⁻⁹ × 100

Q = 1.3273 × 10⁻⁶ C

Q = 1.3273 μC

Charge = 1.3273 μC