A parallel plate capacitor is made up of two plates, each having an area of 8.0x10-4 m2 and separated from each other by 5.0 mm. It is filled with equal thicknesses of dielectrics arranged as shown. What is its capacitance?
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Answer:
Here there are three capacitors in between the plates and they are in series.
C
1
=
d
1
Ak
1
ϵ
0
=
0.4×10
−3
2×2×8.854×10
−12
=8.854×10
−8
F
C
2
=
d
2
Ak
2
ϵ
0
=
0.6×10
−3
2×3×8.854×10
−12
=8.854×10
−8
F
C
3
=
d
3
Ak
3
ϵ
0
=
1.2×10
−3
2×6×8.854×10
−12
=8.854×10
−8
F
thus, C
1
=C
2
=C
3
=C
C
eq
1
=
C
1
+
C
1
+
C
1
=
C
3
C
eq
=
3
C
=
3
8.854×10
−8
=2.94×10
−8
F
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