Question

A parallel plate capacitor of capacitance 20mf is being charged by a voltage source whose potential is changing at the rate of 3 v/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively :

Answer 1

Answer:

60

Explanation:

Given A parallel plate capacitor of capacitance 20 mf is being charged by a voltage source whose potential is changing at the rate of 3 v/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively

Now capacitance is 20 x 10^-6 f

Rate of change of potential is dv/dt = 3 v/s

q = cv

dq/dt = c dv/dt

         = 20 x 10^-6 x 3

         = 60 x 10^-6

        I c = 60 μ A

We know that displacement current I d = I c = 60 μ A