Question

A parallel-plate capacitor of plate area 100 cm2 and plate separation 1.0 cm is connected across a 100 V battery. The battery is then disconnected and a dielectric slab of thickness 0.50 cm and dielectric constant 7.0 is inserted between the plates. Calculate (a) the capacitance C0 (before the slab is inserted), (b) the free charge Q, (c) the electric field strength E0 in the gap, (d) the electric field strength E in the dielectric, (e) the potential difference V between the plates, and (f) the capacitance C (when the slab is inserted)

Answer 1

Answer:

six

Explanation:

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