Question

A parallel plate capacitor partially filled with dielectric medium of constant K = 3 as
given in the figure. Find the capacitance of capacitor
Al
d
ЗАЕ,
(1)
(2)
d
3AE,
2d
2AE
3d
(3)
Αε,
3d
(4)​

Answer 1

Answer:

where is the figure ? The question jis incomplete.

Answer 2

Answer:

The capacitance of the capacitor partially filled with a dielectric medium of constant K = 3 will be $\frac{3}{2}$$\frac{A\varepsilon_0}{d}$.

Explanation:

This question is formula-based.

We know that the capacitance of a parallel plate capacitor partially filled with a dielectric medium is given as;

$C=$ $\frac{A\varepsilon_0}{d-t+\frac{t}{K}}$      (1)

Where,

C= capacitance of the capacitor

A= area of the plate

$\epsilon o$=permitivity of free space

d= thickness of the capacitor

t= thickness of the dielectric slab

K= dielectric constant

As per the question,

K=3

And as the capacitor is partially filled with the then t=d/2

By putting the value of K and t in equation (1) we get;

$C=$$\frac{A\varepsilon_0}{(d-\frac{d}{2}+\frac{d}{6})}$= $\frac{3}{2}$ $\frac{A\varepsilon_0}{d}$

Hence, the capacitance of the capacitor partially filled with a dielectric medium of constant K = 3 will be $\frac{3}{2}$ $\frac{A\varepsilon_0}{d}$.