Physics, asked by ynil, 10 months ago

A parallel-plate capacitor whose capacitance C is 13,5 pF is charged by a battery to a potential difference V = 12,5 V between its plates. The charging battery is now disconnected, and a porcelain slab (κ = 6,5) is slipped between the plates. a) What is the potential energy of the capacitor before the slab is inserted ? b) What is the potential energy of the capacitor-slab device after the slab is inserted?

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Answered by VIGYAS
1

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