Question

A parallel plate capacitor with air as medium between the plates has a capacitance of 10uf.The area of capacitor is divided into 2 equal halves and filled with 2 media having dielectric constants k1

Answer 1

Answer:

it is a hard question

Explanation:

Answer 2

Given that,

Capacitor = 10μf

Suppose,  two media having dielectric constant k₁ =2 and k₂ = 4 The capacitance will now be :

We know that,

Capacitor is

$C = \dfrac{\epsilon_{0}A}{d}=10\ \mu f$

Now two capacitors C₁ and C₂  connected in parallel

Then the capacitance of each part is

For first plate,

$C_{1}=\dfrac{k_{1}\epsilon_{0}A_{1}}{d}$

For second plate,

$C_{2}=\dfrac{k_{2}\epsilon_{0}A_{2}}{d}$

We need to calculate the equivalent capacitor

Using formula of parallel

$C=C_{1}+C_{2}$

Put the value into the formula

$C=\dfrac{k_{1}\epsilon_{0}A_{1}}{d}+\dfrac{k_{2}\epsilon_{0}A_{2}}{d}$

Here, Area is

$A_{1}=A_{2}=\dfrac{A}{2}$

$C=(K_{1}+k_{2})(\dfrac{\epsilon_{0}A}{2d})$

Put the value into the formula

$C=(2+4)\dfrac{10}{2}$

$C=30\ \mu f$

Hence, The equivalent capacitor is 30 μf.