Physics, asked by akashpshinde2, 3 months ago

A parallel plate capacitor, with air between its plates and having capacitance C
is fully charged by a battery of emf V volt. Then the battery is disconnected.
Now the separation between the plates of the parallel plate capacitor is doubled.
In what way will the following physical quantities be affected ?
(i) Capacitance, (ii) Charge, (iii) Potential difference between the plates, (iv) Strength
of electrostatic field between the plates, and (v) the electrostatic potential energy
stored in the capacitor per unit volume. State reason for your answer in each case.​

Answers

Answered by Anonymous
5

Explanation:

ii}. Charge

I hope it may help to you

Similar questions