A parallel plate capacitor with air between the plates has a capacitance of 8 pF.The separation between the plates is now reduced by half and the space between them is filled with a medium of dielectric constant 5. Calculate the value of capacitance of parallel plate capacitor in second case,
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initially,
c=E•A/d=8pF
now ,
the separation between the plates is reduced by half (d/2)and the space between them is filled with a medium of dielectric constant (K=5)
we know that in presence of a dielectric the capacitance increases
c'=K c
c'=KE•A×2/d
c'=5×2E•A/d
c'=10E•A/d
c'=10c
c'=80pF
I hope this helps ( ╹▽╹ )
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