A parallel plate capacitor with air between the plates has a capacitance of 10pF. If the distance between the plates is made double and the space between them is filled with a dielectric of dielectric constant 10, then find the new capacitance.
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A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10-12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6? Therefore, the capacitance between the plates is 96 pF.
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