Physics, asked by MiniDoraemon, 5 months ago

A parallel plate capacitor with air between the plates has a capacitance of 9pF. The separation between its plates is d . the space between the plate is now filled with two dielectrics. one of the dielectrics has dielectrics constant k₁ = 3 and thickness d/3 while the other one has dielectric constant k₂ = 6 and thickness 2d/3 . capacitance of the capacitor is now .[AIEEE 2008]​

Answers

Answered by urvashirx
4

Explanation:

The air filled capacitance , C=dAϵ0=9pF

According to question there are two capacitor with capacitances C1 and C2 . and they are in series .

Here, C1=(d/3)Ak1ϵ0=9dAϵ0=9C    as k1=3

and C2=(2d/3)Ak2ϵ0=9dAϵ0=9C    as k2=6

The equivalent capacitance, Ceq=C1+C2C1C2=9C+9C(9C)(9C)=29C=(9/2)9=40.5pF

please ♥️

please⭐

please mark me as brilliant

Answered by nehaimadabathuni123
2

HOPING THIS WILL HELP YOU PLZ MARK AS BRAINLIEST AND FOLLOW ME

Attachments:
Similar questions