A parallel plate capacitor with air between the plates has a capacitance of 9pF. The separation between its plates is d . the space between the plate is now filled with two dielectrics. one of the dielectrics has dielectrics constant k₁ = 3 and thickness d/3 while the other one has dielectric constant k₂ = 6 and thickness 2d/3 . capacitance of the capacitor is now .[AIEEE 2008]
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Explanation:
The air filled capacitance , C=dAϵ0=9pF
According to question there are two capacitor with capacitances C1 and C2 . and they are in series .
Here, C1=(d/3)Ak1ϵ0=9dAϵ0=9C as k1=3
and C2=(2d/3)Ak2ϵ0=9dAϵ0=9C as k2=6
The equivalent capacitance, Ceq=C1+C2C1C2=9C+9C(9C)(9C)=29C=(9/2)9=40.5pF
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