A parallel plate capacitor with air between the plates has a capacitance of 10pF. If the distance between the plate is made double, and the space between them is filled with a dielectric constant 10, find the new capacitance
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Answer:
K=10pF K=4 C
1
=
d
ε
0
A
=10μF...(i)
and C
2
=K
d/2
ε
0
A
=
d
4×2ε
0
A
=8×10=80pF
Explanation:
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