Question

A parallel plate capacitor with circular plates of radius r is being charged. At the instant shown displacement current in the region between the plates enclosed between r/2 and r is

+ -
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i-----| |-----i
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Answer 1

Explanation:

here it is ............

Answer 2

Answer:

Displacement current =

$\frac{1}{4} i$

Explanation:

Displacement current is given by

$I = \epsilon_{0}\frac{d\phi_{e} }{dt}$

$= \epsilon_{0}A\frac{dE}{dt}$

because $( \phi = A.E.)$

$= A\frac{d\frac{q}{A} }{dt}$

= $\frac{A_{1} }{A}i$

= $\frac{\pi( \frac{R}{2}^{2} )}{\pi R^{2} }i$

$= \frac{1}{4} i$

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