Physics, asked by sanjithkumar7568, 9 months ago

A parallel-plate capacitor with plate area 20 cm2 and plate separation 1.0 mm is connected to a battery. The resistance of the circuit is 10 kΩ. Find the time constant of the circuit.

Answers

Answered by shiva1018
0

Answer:

I don't know the answer

Explanation:

i think 2

Answered by shilpa85475
1

The circuit’s time constant is 0.18 μs.

Explanation:

Plates’ area, A = 20 cm2 = 20 \times 10−4 m2

Between the plates, the separation is d = 1 mm = 1 \times 10−3 m,

Circuit’s resistance, R = 10 kΩ

A parallel-plate capacitor’s capacitance,

C = ∈0 Ad = 8.85 \times 10-12 \times 20 \times 10 – 41  \times 10-3 =17.7  \times 10-12 F

Time constant is measured as CR

= 17.7 \times 10-12 \times 10 \times 103

= 0.18 μs

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