Question

A parallel plate capacitor with plate area 'A' and separation 'd' is filled with two dielectric materials as shown in the figure.
The dielectric constants are K, and K2 respectively. Find the effective capacitance of the system.
Ds
K
d2
+
d/2
K₂​

Answer 1

Answer:

Capacitance of first half of the capacitor of width d/2=C

1

=

d/2

K

1

Aϵ

0

=

d

2K

1

Aϵ

0

Similarly the capacitance of other half =C

2

=

d

2K

2

Aϵ

0

These two capacitance are connected in series.

Thus, the net capacitance of the combination is, C

eff

=

C

1

+C

2

C

1

C

2

=

d

2Aϵ

0

(

K

1

+K

2

K

1

K2)