Physics, asked by prateek3377, 1 year ago

A parallel plate capacitor with the plate area 100 cm2 and the seperation between the plate 1 cm is connected across a battery of emf 24 v the force of attraction between the plate is

Answers

Answered by schuylercoelho2020
0

Answer:

A = 100cm2 = 10–2m2 d = 1cm = 10–2m V = 24V0 ∴ The capacitance C ∴ The energy stored C1 = (1/2) CV2 = (1/2) × 10–12 × (24)2 = 2548.8 × 10–12

Explanation:

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