Question

a parallel plate capacitor with the plate area 100cm2 and the separation between the plates 1 cm is connected across a battery of emf 24 volts. Find the force of attraction between the plates.

Answer 1

The formula for force btwn the capacitor plates is almost same as ENERGY excpet just 'd' comes in denominatior.Remember these throu energy stored formulas.U wont have prblem in remembering them!!

Answer 2

Answer:

2.549 * 10⁻⁷ N

Explanation:

A = 100 cm² = 10⁻² m²

d = 1 cm = 10⁻² m

V = 24 V

C = ε₀ A/d

ε₀ = 8.85 * 10⁻¹²

C = 8.85 * 10⁻¹² *  10⁻²/10⁻²

=> C =  8.85 * 10⁻¹²

Energy stored = (1/2)CV²   = (1/2)  8.85 * 10⁻¹² (24)²

Force between plated = Energy stored / Distance

= (1/2)  8.85 * 10⁻¹² (24)² / 10⁻²

= 2548.8 * 10⁻¹⁰

= 2.549 * 10⁻⁷ N