A parallel plate condenser has a capacitance 50 micro farad in air and 110 micro farad when immersed in a oil. The dielectric constant of the oil is
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Answered by
21
Answer ⇒ k = 2.4
Explanation ⇒ When any dielectric material is inserted then the new capacitance will be given by,
New Capacitance = Dielectric constant × Old Capacitance.
In Parallel plate capacitor,
Old Capacitance = 50 μF.
New Capacitance = 110 μF.
Thus, Dielectric constant (k) = 110/50
k = 11/5
∴ k = 2.4
Hope it helps.
Answered by
5
Answer:
Old Capacitance = 50 μF.
New Capacitance = 110 μF.
Thus, Dielectric constant (k) = 110/50
k = 11/5
∴ k = 2.4
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