Question

A parallelogram ABCD and rectangle ABEF have the same base AB and equal area. Then prove that the perimeter od parallelogram is greater than the rectangle.​

Answer 1

Answer:

prove triangles congruent

Answer 2

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=> Opp sides of ||gm and rect are equal. 

=> AB = DC        

   => AB = EF       

=> DC = EF (1) 

=> AB + DC

= AB + EF  (Adding AB in both sides) (2) 

=> The perpendicular segment is the shortest

=> BE < BC & AF < AD

 => BC > BE & AD > AF

 => BC + AD > BE + AF (3) => Adding (2) and (3)

=> AB + DC + BC + AD > AB + EF + BE + AF 

=> AB + BC + CD + DA > AB + BE + EF +FA 

=> P of  ABCD > P of ABEF                                     

Proved