Question

a parallelogram ABCD in which AB=8.5cm and its perimeter is 24cm. find the length of each of its remainig sides

Answer 1

Given:
ABCD is a parallelogram in which AB=8.5cm and the perimeter of parallelogram is 24cm

To find:
BC,CD and AD

Solution:
AB=CD(opposite side of ||gram is equal)
So, CD=8.5cm

As,the perimeter of parallelogram is
=>sum of all sides
So,
AB+BC+CD+DA=24cm
8.5+BC+8.5+DA=24cm
17+BC+DA=24cm
17+2BC=24cm(as,BC and DA are opp.sides,so BC=DA)

=>2BC=24-17
=>2BC=7
=>BC=7/2
=>BC=3.5cm

as, DA=BC(opp. sides are equal)
So,DA=3.5cm

So,
AB=8.5cm
BC=3.5cm
CD=8.5cm
DA=3.5cm
Perfectly definitely pure correct answer
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Answer 2

ANSWER:-

AB=CD(opposite side of llgram is equal) So, CD=8.5cm

AB=CD(opposite side of llgram is equal) So, CD=8.5cmAs,the perimeter of parallelogram is => sum of all sides

sum of all sidesSo,

sum of all sidesSo,=> AB+BC+CD+DA=24cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA are

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7=>BC=7/2

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7=>BC=7/2=>BC=3.5cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7=>BC=7/2=>BC=3.5cmAs, DA=BC(opposite sides are equal) So, DA=3.5cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7=>BC=7/2=>BC=3.5cmAs, DA=BC(opposite sides are equal) So, DA=3.5cmAB=8.5cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7=>BC=7/2=>BC=3.5cmAs, DA=BC(opposite sides are equal) So, DA=3.5cmAB=8.5cmBC=3.5cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7=>BC=7/2=>BC=3.5cmAs, DA=BC(opposite sides are equal) So, DA=3.5cmAB=8.5cmBC=3.5cmCD=8.5cm

sum of all sidesSo,=> AB+BC+CD+DA=24cm=> 8.5+BC+8.5+DA=24cm=> 17+BC+DA=24cm=> 17+2BC=24cm(as, BC and DA areOpposite sides, so BC=DA.=>2BC=24-17=>2BC=7=>BC=7/2=>BC=3.5cmAs, DA=BC(opposite sides are equal) So, DA=3.5cmAB=8.5cmBC=3.5cmCD=8.5cmDA=3.5cm