A parallelogram ABCD is constructed with sides AB 4cm BC 6cm and Angle ABCD 90 Degree. Then ABCD a___
Answers
Step-by-step explanation:
construct a structure it requires few processes.
=> ABCD is a parallelogram
=> Angle B = 60°
__________________________
=> So make a straight line more than 6 cm..
=> take the length BC on compass and cut the straight line with same length.
=> take a few distance from point B, make a semicircle and putting it on the point where it coincides with the straight line. Cut the arc on that semicircle.. Thus the angle will be 60°
=> With the same measurement cut an arc on point C too making 60° angle
=> Draw straight lines from B that connects the bisection of arc and extend it further.
Similarly do that from C.
=> take Ab length on compass and cut the straight line such that a cross be made on that.
Similarly on other side too.
=> now connect the two cuts..
U will get the required parallelogram.
_____________________
Checking
=-=-=-=-=-=-
=> measure each side by scale and check whether AD and BC are of required lengths and AB and BC are of required lengths.
=> check the angle with protractor.
________________________
Hope this is ur required answer
Proud to help you
Answer:
20 cm
Step-by-step explanation:
Answer
⇒ Draw a line segment AB = 6cm.
⇒ Construct an angle of 60∘ at point B.
⇒ Cut off BC = 4cm.
⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120∘ at point A and C which meet at point D.
⇒ Thus, ABCD is a required parallelogram.
⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )
⇒ Perimeter of parallelogram ABCD=2(a+b)
⇒ 2(6+4) [From( 1 )]
∴ Perimeter of parallelogram ABCD=20cm.