Math, asked by muskanbulbuliya, 3 months ago

a parallelogram and a triangle have a common base if area of the triangle is 20cm² the find area of parallelogram ?​

Answers

Answered by amitnrw
1

Given : a parallelogram and a triangle have a common base  

area of the triangle is 20cm²

To Find : area of parallelogram

Solution:

Area of triangle = (1/2) * base * height

Area of Parallelogram  = base * height

parallelogram and a triangle have a common base  b = b

and  if vertex of triangle  lie of opposite side of parallelogram

Then h will also be common

Then Area of Parallelogram  = 2   (1/2) * base * height

=> Area of Parallelogram  = 2 Area of triangle

=>  Area of Parallelogram  = 2  * 20

=>  Area of Parallelogram  = 40  cm²

If third vertex in not on opposite side of parallelogram / or in line of that

then we can not find any relation.

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Answered by pulakmath007
2

SOLUTION

GIVEN

  • A parallelogram and a triangle have a common base

  • Area of the triangle is 20cm²

TO DETERMINE

The area of parallelogram

EVALUATION

Let b cm be the base of the triangle

Since the parallelogram and the triangle have a common base

So base of the parallelogram = b cm

Let h cm be the height of the triangle

Then altitude of the parallelogram = h cm

Then area of the triangle

 \displaystyle \sf{ =  \frac{1}{2}bh \:  \:  {cm}^{2}  }

So by the given condition

 \displaystyle \sf{ \frac{1}{2}bh  = 20 }

 \implies \:  \displaystyle \sf{  bh \:  \:   = 40 }

So area of the parallelogram

= bh cm²

= 40 cm²

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