A parallelogram given and it's diagonal 16cm and 30cm. Find its perimeter
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Given: Diagonals AC=30cm and DB=16cm.
Since the diagonals of the rhombus bisect at right angle to each other.
Therefore, OD= DB/2=16/2=8cm
and OC= AC/2=30/2=15cm
Now, In right angle triangle DOC,
(DC)²=(OD)²+(CO)²
⇒(DC)² =(8)²+(15)²
⇒(DC)² =64+225=289
⇒DC= √289=17cm
Perimeter of the rhombus=4× side
=4×17=68cm
Thus, the perimeter of rhombus is 68 cm.
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