A parallelogram has one angle that measures 95°. What are the measures of the other three angles in the parallelogram?
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Answered by
25
In a parallelogram opposite angles are equal
so,Let the parallelogram be ABCD
Angle A given 95°
therefore Angle C= Angle A =95°
Now another to let be x
x+x+95+95=360(sum of angle of quadrilateral is 360(
2x+190=360
2x=360-190
2x=170
x=170/2
x=85°=another 2 angle...
I hope it will help uh....
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so,Let the parallelogram be ABCD
Angle A given 95°
therefore Angle C= Angle A =95°
Now another to let be x
x+x+95+95=360(sum of angle of quadrilateral is 360(
2x+190=360
2x=360-190
2x=170
x=170/2
x=85°=another 2 angle...
I hope it will help uh....
Please mark me as brainliest...❤❤
shruti5285:
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Answered by
9
let ABCD be the four angles of given parm
if √ABC =95° then √BCD=85°( as √ABC+√BCD =180° being co-interiro angle)
now,
√ABC=√ADC =95°(opposite angles of parm are equal)
again,
√BCD=√BAD=85°(same as above)
hence the measures of other three angles are 95°,85° and 85°
if √ABC =95° then √BCD=85°( as √ABC+√BCD =180° being co-interiro angle)
now,
√ABC=√ADC =95°(opposite angles of parm are equal)
again,
√BCD=√BAD=85°(same as above)
hence the measures of other three angles are 95°,85° and 85°
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