Math, asked by nikhil080820054591, 3 months ago

- A parallelogram has two of its adjacent sides mea-
suring 13 each. Find the sum of the squares of its
diagonals.
(a) 169
(b) 338
(c) 676
(d) 507​

Answers

Answered by rockysingh91
1

338

since we know that the shape is a rhombus

so its diagonal intersect ar right angles ,

in such a way that (a square + b square = 13 square)

so a^2 + b^2 + a^2 + b^2)

2(a^2 + b^2)

2(13^2)

2×169

338

Ta Daa!

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