a parallelogram PQRS, diagonals PR and SQ intersect at O. If SQ = 5 PR and = OP = 4.5 cm, find OS.
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Given:
If SQ = 5 PR and = OP = 4.5 cm
To find:
The length of the OS.
Solution:
As we know that the diagonal of the parallelogram bisect each other at their intersection point.
So for the Diagonal PR
- PO = OR
And for the Diagonal SQ
- SO = OQ
We have given the side OP as 4.5 cm so the length of the Diagonal PR will
- 2×4.5 = 9cm
As we have:
- SQ = 5PR
- SQ = 5×9
- SQ = 45cm
So the length of OS is SR/2
- OS = 45/2
- OS = 22.5
The length of the OS is 22.5 cm
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