a parallelogram PQRS has one side QR=5cm sq. DE is perpendicular to AB if the second side of the parallelogram is 10 cm find AE
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Step-by-step explanation:
Answer:
Here it is
Step-by-step explanation:
Area of a parallelogram=Base×Height
So, Height=Area of parallelogram/Base
Therefore,
DE=54cm^2/AB
=(54/9)cm
=6cm
AD^2=DE^2+AE^2 (Pythagoras Theorem)
So, AE^2=AD^2-DE^2
=>AE=√(AD^2-DE^2)
=√(10^2-6^2)
=√[(10+6)(10-6)]
[a^2-b^2=(a+b)(a-b)]
=√[16×4]
=√64
=8cm
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