A parallelogram whose adjacent sides are 20 cm and 42 cm has one diagonal 38 cm. find its altitude with side 42 cm.
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keeping base as 42 and drawing a perpendicular with height h to it we will get 2 equations
h^2+x^2= 38^2 ... eq 1
h^2+ (42-x)^2=20^2 ...eq 2
x can be solved using the abv and you ll get your altitude h by replacing x in eq 1
h^2+x^2= 38^2 ... eq 1
h^2+ (42-x)^2=20^2 ...eq 2
x can be solved using the abv and you ll get your altitude h by replacing x in eq 1
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