Question

A parallelogram with an angle equal to 90 degree has diagonals of lengths 6cm and 8cm.it is a​

Answer 1

Answer:

Both diagonals of parallelogram are given then take AC = 8cm and BD = 6m.

Steps of construction :

⇒ Draw a line segment AC = 8cm.

⇒ With center A and radius more than half of AC, draw arcs, one on each sides of AC.

⇒ With center B and same radius, draw arcs cutting the previous arcs P and Q respectively.

⇒ Join PQ which is perpendicular to BC and bisects BC at half.

⇒ Construct an angle 60

∘

at O on both sides of AC that is above and below.

⇒ Then draw the line through an angles which will be passing through pint O.

⇒ Cut off OD = 3cm and OB = 3cm. Then we get DB = 6cm.

⇒ Join AD, DC, BC and BA.

Thus, ABCD is the required parallelogram

Answer 2

Answer:

Both diagonals of parallelogram are given then take AC = 8cm and BD = 6m.

Steps of construction :

⇒ Draw a line segment AC = 8cm.

⇒ With center A and radius more than half of AC, draw arcs, one on each sides of AC.

⇒ With center B and same radius, draw arcs cutting the previous arcs P and Q respectively.

⇒ Join PQ which is perpendicular to BC and bisects BC at half.

⇒ Construct an angle 60

∘

at O on both sides of AC that is above and below.

⇒ Then draw the line through an angles which will be passing through pint O.

⇒ Cut off OD = 3cm and OB = 3cm. Then we get DB = 6cm.

⇒ Join AD, DC, BC and BA.

Thus, ABCD is the required parallelogram.

Step-by-step explanation:

i hope this helps u