A paralleogram the length of whose sides are 11 and 13 and has one daigonal 20 fond the length of another daigonal
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Answer:
Area of parallelogram=1/2 (diagonal 1)×(diagonal 2)
it is also equal to product of its sides i.e=l×b
hence
1/2×d1×d2=l×b
given d1=20
l=11
b=13
hence d2=14.3
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