Question

A paramagnetic substance in the form of a cube with sides 11 cm has a magnetic dipole moment of 20 x 10⁻⁶ J/T when a magnetic intensity of 60 x 10³ A/m is applied. Its magnetic susceptibility is:
(A) 3.3 × 10⁻²
(B) 40.3 × 10⁻²
(C) 2.3 × 10⁻²
(D) 3.3 × 10⁻⁴

Answer 1

Answer:

3.3 × 10^-4

Explanation:

susceptibility(¥)

¥ = M / H

( M= Magnetic moment per unit volume)

(H = magnetising field)

M = m /V ( m = magnetic dipole moment )

M = 20 × 10^-6 / 10^-6 ( volume = a^3)

H = 60 × 10^3

therefore

¥ = 20 / 60 × 10^3 = 3.3 × 10^-4.

hope it helps..