A parcel of 12 books contains 4 books with loose binding what is the prob. That a random
selection of 6 books (without replacement) will contain 3 books with loose binding?
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Here at least 2 are defective out of 4. So the defective can be 2 or defective can be 3.
Total defective =3
If 2 are defective =3C2*7C2=63
If 3 are defective =3C3*7C1=7
Probability that 2 out of 4 are defective=63+7/10C4=70/210=1/3
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