Question

A paricle moves in a straight line in such a way that its velocity v at any position is given by v^2=2-3x,where x is measured from a fixed point. The acceleration of particle is

Answer 1

Answer:

-3÷(2×√(2-3x))

Explanation:

to find acceleration, you have to find the first derivative of velocity. that is, you need to find an expression for velocity in v (not v²) and then you need to differentiate it with respect to time.

v²=2-3x

v=√(2-3x)

dv/dt = 1/2 *((2-3x)^-1/2) *-3

         = -3÷(2×√(2-3x))

then substitute any values of x to find a at that particular point.

hope that helps!!