A paricle moves towards east for 2 sec with velocity 15 m/s and move towards north for 8 sec with
velocity 5 m/s. Then average velocity of the particle is:
(1) 1 m/s
(2)5 m/s
(3) 7 m/s
(4) 10 m/s
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Answer:
3 7m/s
Explanation:
plz mark brainliest it take 10 min to solve it
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☆average velocity = total displacement/total time taken
S1= velocity ×time
= 15×2(east)
=30î
S2= 5×8(north)
=40j^
•S1+S2=30î+40j
=50m
•time taken=8+2=10secs
Vav=50/10
=5m/s
hope it helps!
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