Question

A paricle of mass 4kg is thrown from ground at angle of 53 with speed 50m/s . calculate torque at any time t where t

Answer 1

Answer:

HOPE IT HELPS.!!!!!!.

Explanation:

Time of flight =

g

2usinθ

=

10

2×80×sin30

o

=8

As particle during journey at t=2sec and at t=6sec will be at same height and hence vertical displacement is zero.

Horizontal displacement =(ucosθ)×(6−2)

=80×

2

3

×4

=160

3

m

∴ Average velocity =

4

160

3

=40

3

m/sec

Answer 2

the above ans by ritamriyu12 is correct