Question

A paricle of mass 6mg carrying acharge of 10^-9 C is placed in the electric field of strength e=6×10^5 v/m , the acceleration req by the particle is.

a)
${10}^{2}$
b)
${10}^{5}$
c)
${10}^{3}$
d)
${10}^{20}$

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Answer 1

Answer:

${10}^{ - 4}$

this comes from my calculations...pls don't report....I mean my logic says this is the answer.

Explanation:

given

• q= 10^-9 C
• E=6×10^5 v/m
• m=6mg

now we know that F=qE and also F=ma

hence

qE=ma

10^-9 × 6×10^5 = 6a

a=(10^-9×6×10^5)/6

=10^-4 m/s²

I know that my answer doesn't match with any of the options given ...

so whoever views this answer...pls tell me the proper procedure to solve the question...thanks in advance ⚛️⚛️.

Answer 2

Answer:

Answer:

{10}^{ - 4}10

−4

this comes from my calculations...pls don't report....I mean my logic says this is the answer.

Explanation:

given

q= 10^-9 C

E=6×10^5 v/m

m=6mg

now we know that F=qE and also F=ma

hence

qE=ma

10^-9 × 6×10^5 = 6a

a=(10^-9×6×10^5)/6

=10^-4 m/s²

I know that my answer doesn't match with any of the options given ...

so whoever views this answer...pls tell me the proper procedure to solve the question...thanks in advance ⚛️⚛️.

Explanation:

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