Question

a paricle when thrown , moves such that it passes from same height at 3 and 10s, the height is​

Answer 1

Answer:

Explanation:

If t1 and t2 are the time when body is at the same height

Then  

h = ½ * g* t1 * t2

h = ½* g * 2 * 10

h = 10 g