Physics, asked by jaideepreddy5348, 11 months ago

A park has a radis of 10 m. If a vehicle goes round it at an averge speed of 18 km/hr, what shoud be the proper angle of banking?

Answers

Answered by Anonymous
4

Answer:

Hey!

Given that r=10m and v=18km/hr=5m/s

Let θ be the angle of banking

⟹tanθ= rgv2

= 10025

= 41

⟹θ=tan −1 ( 41 )

Thank You ❤️

Answered by NITESH761
0

Explanation:

We know that,

\boxed{\sf tan \: θ = \dfrac{v^2}{rg}}

\sf \longmapsto \dfrac{(5)^2}{10×10}

\sf \longmapsto \dfrac{1}{4}

\sf \longmapsto θ= tan^{-1} \bigg( \dfrac{1}{4} \bigg)

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