Question

A park in the shape of a quadrilateral ABCD c =90° BC=12m CD=5m and AD =8m . Find the area of the quadrilateral ABCD.​

Answer 1

Area=square root of s(s-a)(s-b)(s-c)

s=30/2=15

s-a=15-9=6

s-b=15-8=7

s-c=15-5=10

square root 15×6×7×10×square root 396

square root 6300

=20.98cm².

So, the area is 20.98cm².