Question

A park, in the shape of a quadrilateral
ABCD, has angle C=90°, AB=9m, BC=12m,
CD=5m and AD=8m.How much area does
It occupy?

Answer 1

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Answer 2

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A park, in the shape of a quadrilateral

ABCD, has angle C=90°, AB=9m,BC=12m,

CD=5m and AD=8m.How much area does ,It occupy?

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30 m²

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${\huge{\underline{\underline{\mathcal {\red{♡Solution♡}}}}}}$

Given:-

• ABCD is a quadrilateral.

• C =90°

• AB = 9m , BC = 12m , CD = 5m , AD = 5m

To find :-

Area of ∆BCD

Total area of Park = Area of ∆ABD + ∆BCD

Area of ∆BCD

Since, DC=5m and BC = 12m , angle C = 90°

Then ∆BCD is a right angled triangle

Area of ∆BCD → ½ × base × height

→ ½ × 12 × 5 m²

→ 6 × 5 m²

→ 30 m²

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