A park, in the shape of a quadrilateral
ABCD, has angle C=90°, AB=9m, BC=12m,
CD=5m and AD=8m.How much area does
It occupy?
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A park, in the shape of a quadrilateral
ABCD, has angle C=90°, AB=9m,BC=12m,
CD=5m and AD=8m.How much area does ,It occupy?
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30 m²
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Given:-
• ABCD is a quadrilateral.
• C =90°
• AB = 9m , BC = 12m , CD = 5m , AD = 5m
To find :-
Area of ∆BCD
Total area of Park = Area of ∆ABD + ∆BCD
Area of ∆BCD
Since, DC=5m and BC = 12m , angle C = 90°
Then ∆BCD is a right angled triangle
Area of ∆BCD → ½ × base × height
→ ½ × 12 × 5 m²
→ 6 × 5 m²
→ 30 m²
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