Question

A park in the shape of a quadrilateral ABCD has C = 90°. AB = 18 m, BC = 24 m, CD = 10 m and AD = 16 m. How much area does it occupy?​

Answer 1

Answer:

arpox area = 262

Step-by-step explanation:

hope it is useful

Answer 2

Class 8>>Maths>>Mensuration>>Area of General Quadrilateral>>A park in the shape of a quadrilateral A

Question

Area of △BCD=21×24×10=120m2

Use pythagoras theorem in ΔCBD

CD²+BC²=DB²

10²+24²=DB²

676=DB²

⟹DB=26m

Area of △ABD⇒ (By heron's) 

S=226+18+16/2=30

A=under root using .30(30_26)(30_18)(30_16)

=141.98≈142m2

∴ Total area =142+120=262m²