Question

A park in the shape of a quadrilateral ABCD has C = 90°. AB = 18 m, BC = 24 m, CD = 10 m and AD = 16 m. How much area does it occupy? With full methods and solutions will be marked as brainlist​

Answer 1

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>>A park in the shape of a quadrilateral A

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A park in the shape of a quadrilateral ABCD has C=90

0

. AB=18m, BC=24m, CD=10m and AD=16m. how much area does it occupy?

Medium

Solution

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Area of △BCD=

2

1

×24×10=120m

2

Use pythagoras theorem in ΔCBD

CD

2

+BC

2

=DB

2

10

2

+24

2

=DB

2

676=DB

2

⟹DB=26m

Area of △ABD⇒ (By heron's)

S=

2

26+18+16

=30

A=

30(30−26)(30−18)(30−16)

=141.98≈142m

2

∴ Total area =142+120=262m

2

Answer 2

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