A park, in the shape of quadrilateral ABCD, has angle C=90° ,AB= 9m, BC=12m CD=5m and AD=8m. How much area does it occupy?
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As CD is given perpendicular so it is the height of the Quadrilateral.
Area of trapezium = ½ × Sum of parallel sides × height
= ½ × (8+12)×5
= ½ × 20 × 5 = 50 m²
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In cyclic quadrilateral PQRS 5×angle Q = 7× angle S then, find angle Q.
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