Math, asked by misspiru20, 11 months ago

A park is 1500 m long and 750 m wide . A cyclist had to take 4 rounds of this park. How much time will he take at the speed of 4.5 km/ h ?​

Answers

Answered by BrainlyPromoter
9

Answer:

4 hours

Step-by-step explanation:

It can be assumed from the question that the park is in the shape of a rectangle. Hence,

Length of the park, l = 1500 m

Length of the park, l = 1500 mBreadth of the park, b = 750 m

Perimeter of the park, P = 2 ( l + b ) = 2 ( 1500 + 750 ) = 2 * 2250

=> Perimeter of the park = 4500 m

Distance to be covered by the cyclist, D = 4 rounds of the park

=> D = 4 * 4500

=> D = 18000 m = 18 km

Now, it's given in the question that, "Speed at which the cyclist is moving is 4.5 km/h".

We know that, time taken to cover the distance is equal to the distance by the speed.

Hence,

Time taken by cyclist, T = 18 / 4.5

=> T = ( 18 * 10 ) / 45

=> T = 180 / 45

=> T = 12 / 3

=> T = 4 hours

Therefore,

Time taken by the cyclist to complete four rounds of the park = 4 hours

#bal

#answerwithquality

Answered by Anonymous
22

\huge{\underline{\underline{\red{\mathfrak{Answer :}}}}}

\tt Given \begin{cases} \sf{Length \: of rectangular \: field \: is \: 1500 \: m. } \\ \sf{Breadth \: of \: rectangular \: field \: is \: 750 \: m.} \\ \sf{A \: cyclist \: had \: to \: take \: 4 \: rounds \: of \: the \: field} \\ \sf{Speed \: is \: 4.5 Kmh^{-1}}\end{cases}

_____________________________

To Find :

 \hookrightarrow \sf{We \: have \: to \: find \: the \: time \: taken}

_____________________________

Solution :

To find the distance We have to find the perimeter of the rectangular field.

We know that,

\large{\star{\underline{\boxed{\sf{Perimeter = 2(Length + Breadth)}}}}}

Perimeter = 2(1500 + 750)

Perimeter = 2(2250)

Perimeter = 4500 m

\large{\star{\underline{\boxed{\sf{Perimeter = 4500 \: m}}}}}

\rule{150}{2}

He had to take 4 rounds. So, multiply perimeter by 4

Distance = 4500 * 4

Distance = 18000 m = 18 km

\large{\star{\underline{\boxed{\sf{Distance = 18 \: km}}}}}

\rule{200}{2}

\large{\star{\underline{\boxed{\sf{Time = \frac{Distance}{Speed}}}}}}

Time = 18/4.5

Time = 4 hr

\large{\star{\underline{\boxed{\sf{Time = 4 \: hours}}}}}

\rule{200}{2}

#answerwithquality

#BAL

Similar questions