: a park is 25 4/5 m long and 20 2/3 m wide .find the perimeter. of a walkway is to be constructed inside teh park which is 2 3/8m wide, what would be the inside perimeter of the walkway
Answers
Given : a park is 25 4/5 m long and 20 2/3 m wide . a walkway is to be constructed inside the park which is 2 3/8m wide,
To find : perimeter of park
inside perimeter of the walkway
Solution:
Park length 25 4/5 m = 25 + 4/5 m = (125 + 4)/5 = 129/5 m
Park Width = 20 2/3 m = 20 + 2/3 m = (60 + 2)/3 = 62/3 m
Park perimeter = 2 ( Length + Width )
= 2 ( 129/5 + 62/3)
= 2( 387 + 310)/15
= 2(697)/15
= 1394 / 15
= 92 14/15 m
walkway is to be constructed inside the park which is 2 3/8m wide
2 + 3/8 m = 19/8 Meter
8 times the width will be reduced
8 * 19/8 = 19 m
inside perimeter of the walkway = 92 14/15 - 19
= 75 14/15 m
Park perimeter = 92 14/15 m
inside perimeter of the walkway = 75 14/15 m
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Answer:
Step-by-step explanation:
Park length 25 4/5 m = 25 + 4/5 m = (125 + 4)/5 = 129/5 m
Park Width = 20 2/3 m = 20 + 2/3 m = (60 + 2)/3 = 62/3 m
Park perimeter = 2 ( Length + Width )
= 2 ( 129/5 + 62/3)
= 2( 387 + 310)/15
= 2(697)/15
= 1394 / 15
= 92 14/15 m
walkway is to be constructed inside the park which is 2 3/8m wide
2 + 3/8 m = 19/8 Meter
8 times the width will be reduced
8 * 19/8 = 19 m
inside perimeter of the walkway = 92 14/15 - 19
= 75 14/15 m
Park perimeter = 92 14/15 m
inside perimeter of the walkway = 75 14/15 m
Learn More:
What is the area of the jogging track which is 2 m wide that runs ...
brainly.in/question/11147790
perimeters of two similar triangles are 30cm and 40cm respectively